Python Day 10

Leap Year
I have a friend Cindy, she was actually born on Feb.29th, and I remember we celebrated her birthday together 2012 in the Maths place!
Leap Year was adapted in Gregorian Calendar. There are Three Criteria:
 The year can be evenly divided by 4, is a leap year, unless:
 The year can be evenly divided by 100, it is NOT a leap year, unless:
 The year is also evenly divisible by 400. Then it is a leap year.
Solution:
def is_leap(year): if year % 4 != 0: print("False") elif year % 4 ==0 and year % 100==0 and year % 40==0: print("Leap Year") elif year % 4==0 and year % 100==0 and year % 40!=0 : print("False") else: print("Leap Year")
Alternative Solutions:
#Alternative Solution def is_leap1(year): return year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)
Output:
print(is_leap(1900)) False
2. Second Largest Number in a List
Suppose we want to find the Second Largest Number in a List
Ex: List=[4,6,3,2,2] Output=4
Solution:
arr=[2,5,4,2] length=len(arr) arr.sort() print(arr[length2])
3. Read an integer N, try to print out 123…N
EX: N=3, Output 123
Solution:
n= int(input()) print(*range(1,n+1), sep="") n=8 1234567
Summary:
we have been working with the Python commands Range, Length, Sort, Module (%), and IfThen(elifthen, else), dfdAs all the books suggested, the Best way to learn to use the knowledge mindfully, so I organized this note 🙂
Happy Practice! 🦁
Reference:
https://www.hackerrank.com/
https://www.geeksforgeeks.org/pythonlargestsmallestsecondlargestsecondsmallestlist/